4.For xDk set equal to xC+( k << 2 ), k=0..nD*2 − 1, the following applies:

–For yDm set equal to yC+( m << 3 ), m=0..nD − 1, the following ordered steps apply:

......

5.For yDm set equal to yC+( m << 3 ), m=0..nD − 1, the following applies:

–For xDk set equal to xC + ( k << 2 ), k = 0..nD*2 - 1, the following ordered steps apply:

In 8.7.1.4 process 4 is related to vertical edge
and process 5 is related to horizontal edge.

However yDk and yDm are same between vertical edge and horizontal edge.
I think that position of vertical edge should be changed as following.

4.For xDk set equal to xC+( k << 3 ), k=0..nD − 1, the following applies:

–For yDm set equal to yC+( m << 2 ), m=0..nD*2 − 1, the following ordered steps apply:

......

5.For yDm set equal to yC+( m << 3 ), m=0..nD − 1, the following applies:

–For xDk set equal to xC + ( k << 2 ), k = 0..nD*2 - 1, the following ordered steps apply: